| Alkyl Halides | ||||
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Chapter
Trihalogen Derivatives ![]() CH3COOH cannot give haloform test due to resonance and does not contain pure COCH3 group.
![]() Halogen and alkali are used as they form OQ Cl or hypohalite ion which is a strong base to replace all 3-‘H’ ![]() The haloform reaction ![]() In the acid-catalyzed halogenation of aldehydes and ketones, rate is independant of the concentration of the halogen; chlorination, bromination, and iodination all at the same rate. Formation of the enolate is rate-determining, and once formed the enolate ion reacts rapidly with the halogen but remember three equivalents are required for haloforms. ![]() This is called the haloform reaction because the trihalomethane produced is chloroform, bromoform, or iodoform depending, of course, on the halogen used. Remember this reaction is done by three equivalent of halogen but if there is only one equivalent of halogen then mono halo product is formed. Normally in seperation test of 2-alkanol or 2-alkanone with other alkanol or alkan one we prefer I2 and alkali for test because formation of yellow ppt of CHI3 takes place. The mechanism of first phase of the haloform reaction begin with a-halogenation through the enolate. The electron-attracting –I effect of an a-halogen increases the acidity of the protons on the carbon to which it is bonded, making each H active and undergo halogenation at that carbon faster than the preceding one. ![]() |















