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Course Material - IIT-JEE, AIEEE, Boards Chapters & Discussions


  
APPLICATION OF DERIVATIVES
Introduction
Dumb Question: How this derived ?

Ans: Let   m1 = tan 1 =
              m2 = tan 2 =
From fiq,   = + 1
           = 2 - 1
          
          


Orthogonal curves: If angle of intersection of two curves is right angle, two curves are c/d orthogonal curves.
If curves are orthogonal,  =



Illustration: Find angle of intersection of curves   y = x2 & y = 4 - x2
For intersection points of given curves,
(x2) = 2x
(4 - x2) = - 2x
At  x = - ,
= 2 x = 2   &   = - 2



  
Both angles are equal.


Length of Tangent, Sub-Tangent, Normal & sub-Normal:

Length of Tangent: Length of segment PT of tangent b/w point of tangent & x-axis is c/d length of tangent.


PT =

Subtangent: Projection of segment PT along x-axis i.e. St c/d subtangent.

Length of Normal: Length of segment PN intercapted b/w point on curve r x-axis.
PN =

Subnormal: Projection of segment PN along x-axis i.e. c/d subnormal.
SN = |y,


Dumb Question: How these relation derived ?

Ans: Since PT makes angle with x-axis, then
tan =

Subtangent = ST = PS cot
But PS = y1   &   cot = [see in fig.]

= cot(90 - PS tan
Subnormal = SN =
Length of tangent = PT =
Length normal = PN =


Illustration: Show that curve y = bex/a. subnormal varies as square of ordinate ?

Ans:
[Dumb Question: What is ordinate ?

Ans: y-axis component is c/d ordi i.e. in P(x1, y1)y1 is ordinate of point P.
y = bex/a ............................................... (i)
differentiating curve   y = bex/a   w.r.t. x.

& Let P(x1, y1) lie on curve

Length of subnormal =
                             
So, subnormal varies as square of ordinate.


       



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