| Complex Numbers |
| Introduction
Why? L.H.S. ![]() ![]() R.H.S. ![]() (iv) Arg ![]() Why ? Let ![]() ![]() ![]() (v) Why ? Let ![]() ![]() ![]() (vi) is purely real Why ? If ![]() ![]() i.e. purely real.(vii ) is purely imaginaryWhy ? If ![]() = ri & -ri Hence purely imaginary either ri or -ri ILLUATRATION - 3. Show that [conj(arg(i)) + i arg(conj(i))] + [conj(arg(-i)) + i arg(conj(-i))] = 0 ![]() ![]() Using above four results we get ![]() ![]() DE - MOIVRE'S THEOREM The theorem states that for any ,
we have![]() Why ? Let ![]() L.H.S. then ![]() & we know taht ![]() R,H.S. Hence ![]() Illustration :- Suppose ![]() So,now find the value of ![]() s Ans:- Now suppose some ![]() ![]() (Using De Movire's Theorem) ![]() Now again using De Moviec's theorem. ![]() ![]() CUBE ROOTS OF UNITY. Cube roots of unity means ![]() Lrt one of cube root of unity b x ,then. ![]() ![]() Solution of this cubic equation will give us three cube roots of unity. ![]() Let us call ![]() Now, ![]() ![]() Therefore 3 cube roots of unity are 1, w, w2. ss Dumb Question:- Why there are 3 solutions ? Ans:- By theory of equation we know that a mnth orider equation will have n solution. Here n is 3 solution PROPERTIES OF CUBE ROOT OF UKNITY. 1. 1 + w + w2 = 0 Why? By theory of equation we know that for any nth order equation, sum of roots = ![]() Here for x3 - 1 = 0 , Sum ![]() Why ? : Again by the theory of Equation product of roots ![]() For x3 - 1 = 0 we have ![]() So product of roots 1, w, w2 = 1.w.w2 = w3 Hence w3 = 1. Now if w3 = 1 Now if nth the Taking nth power on both sides we get (w3)n = 1n gives w3n = 1. 3. ![]() Why : By one of the properties we know that
Hence z = w.So Hence ![]() We also know that w3 = 1 &
Hence ![]() Dumb Question : How can you say taht |w| = 1 Ans : We know that w is cube root of unity . Hence
Taking modulus on both side we get ![]() If w is a cube root of unity then find the value ![]() Ans: (i) ![]() ![]() (ii) ![]() ![]() (iii) ![]() ![]() By (1).(2)& (3) - 1 + w - w = - 1 Hence value is -1 |














is purely real 

i.e. purely real.
is purely imaginary




,
we have























Hence z = w.
Hence 
Hence 
Taking modulus on both side we get 









