Logarithms |
| Introduction
Q10. The value of is greater then 2. true or
false ?Ans:- = Now, 12 > 2 So, or > 2 So, It is true. Logarithms - flow Questions Medium Q1. If a, b, c are distinct positive numbers each different from 1 such that [logba logca - logaa] + [logab logcb - logbb] + [logac logbc - logcc] = 0 then find the value of abc ? Ans:- Let us change all logarithms to base So, the eqn now becomes = 0 where x = etc.So, = 3 or, x3 + y3 + z3 - 3xyz = 0 or, (x + y + z)(x2 + y2 + z2 - xy - yz - zx) = 0 Since we have, x2 + y2
+ z2 - xy - yz - zx = [(x - y)2 + (y - z)2
+ (z - x)2] 0 ** Tip: Writing x2 + y2 + z2 - xy - yz - zx as [(x - y)2 + (y - z)2 + (z - x)2]
which is non-negative for real x, y, z is an useful magnipulation is solving
many questions.So, we calculate x + y + z = 0 that is = 0 or, = 0 or, abc = 1 Dumb Question:- Why x2 + y2 + z2 - xy - yz - zx is not equal to 0 ? Ans:- x2 + y2 + z2 - xy - yz - zx = [(x - y)2 + (y - z)2 + (z - x)2] Now since it is given in question that x, y, z are distinct positive numbers, this cannot be equal to zero. Q2. If loga(ab) = x, then find value of logb(ab) ? Ans:- loga(ab) = logaa + logab = 1 + logab = x So, logab = x - 1 or logba = or, logba + logbb = + 1 => logb(ab) = = Q3. Find the least value of the expression 2 log10x - logx(0.01) for x > 1 Ans:- 2log10x = logx(0.01) = 2 log10 x - logx10-2 = 2(log10x + logx10) = 2(log10x + )= 2 ![]() = 2 + 4So, the minimum value is 4. |


is greater then 2. true or
false ?
2
> 2
= 0 where x =
etc.
= 3
we have, x2 + y2
+ z2 - xy - yz - zx =
[(x - y)2 + (y - z)2
+ (z - x)2]
0
= 0
= 0
)
+ 4


