Trignometric Ratios and Identities |
| Math: Trignometry Chapter
Trignometri Ratios multiples of an angle : 1) sin 2 = 2sin
cos = ![]() why ? sin (A +B) = sin A cos B + cos A sin B Put A = B = ![]() So, sin 2 = 2sin
cos![]() = ![]() = ![]() 2) cos2 = cos2
-sin2 = 1 - 2 sin2
= cos2 - 1 = ![]() 3) tan 2 = ![]() 4) sin 3 = 3 sin
- 4sin2 ![]() Why ? sin3 = sin (
+ 2 )sin ( + 2 )
= sin cos2 +
cos sin2
= sin ( 1 - 2 sin2 )
+ cos (2sin cos )= sin - 2sin3
+ 2sin (1 - sin2 )= 3 sin - 4 sin3![]() 5) cos 3 = 4 cos3
- 3 cos 6) tan 3 = ![]() Illustration 5: sin x + sin y = a and cos x + cos y = b , show that sin (x + y) = and tan (x - y) ![]() Ans:- sin x + sin y = a => 2 sin = a ...................(1)
cos x + cos y = b => 2 cos = b ...................(2) => tan ![]() sin (x + y) = ![]() = ![]() Squaring (1), (2) and adding . 4 cos2 ![]()
= a2 +b2 or cos2 = ![]() sin2 = 1 - ![]() = ![]() tan2 ![]() tan = ![]() Illustration 6:- Find the value of sin180 ? Ans:- Let 180So, 5 = 900=> 2 = 900 - 3 ![]() Or, sin 2 = sin (900 -
3 ) => sin 2 =cos3
=> 2sin cos =
cos (4 cos2
- 3)=> 2sin = 4cos2
- 3 ( cos
0)= 1 - 4sin2 ![]() => 4sin2 + 2 sin
- 1 = 0 So, sin = ![]() = ![]() But since sin > 0 we have sin
= So, sin 18 o = ![]() Dumb Question:- Why cos is
not equal to 0 ? Ans: cos 900 si O and cos Oo is 1 So, cos being a continous function. cos i.e. cos 180 would
have some value between o and 1. |




= 2sin 




and tan (x - y) 
= a ...................(1)
=> tan 



= a2 +b2 



cos
0)



