arranging the given equation
4x^2+25y^2-20xy=6+2x-5y
(2x-5y)^2=6+(2x-5y)
in above eq. take 2x-5y=t
t^2-t-6=0
therefore we hve, t=3 and t=-2
2x-5y=3...eq.M.....and 2x-5y=-2-------eq.K
solving the above two equations with given eq. i.e., 7x-11y=17
we get answers as x=4 and y=1 from solving eq. eq.M and given eq.
and similarly u can find the other set of answers from eq.K and given eq,..
arranging the given equation
4x^2+25y^2-20xy=6+2x-5y
(2x-5y)^2=6+(2x-5y)
in above eq. take 2x-5y=t
t^2-t-6=0
therefore we hve, t=3 and t=-2
2x-5y=3...eq.M.....and 2x-5y=-2-------eq.K
solving the above two equations with given eq. i.e., 7x-11y=17
we get answers as x=4 and y=1 from solving eq. eq.M and given eq.
and similarly u can find the other set of answers from eq.K and given eq,..