Home » Ask & Discuss » Mathematics. » Analytical Geometry « Back to Discussion
Analytical Geometry
Comments (4)
1 Oct 2009 18:10:00 IST
Like
3 people liked this
see shortest distance between any two curve is along their common normal....
we have y^2=4x.
....and x^2+y^2-24y+128=0.....
eqn of normal of parabola is
y=mx-2am-am^3...................(1)here a=1
as this line is also normal to circle ,,,,and normal of circle will pass thru its centre ,,,,,
centre of circle is (0,12)
now it will satisfy (1),,,u will get
am^3+2am+12=0...from here u will get m,,,and then eqn,,,,
then solve eqn wid circle and parabola,,,,
and then find shortest distance b/w them by applying distance formula
hope i helped u....














wait posting solution