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Analytical Geometry
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18 Mar 2010 16:47:31 IST
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let the equation of the tangent be y=mx+a/m
By putting y=0 and x-=0,
the point T is (-a/m^2,0)
and the point Y is (0,a/m)
Since TAYG is a rectangle, the coordinates of G are (-a/m^2,a/m)
[x distances and y distances]
By comparing with the options, C choice is best satisfied by the point G!













The locus of G is y2 + ax= 0.
So, the answer is (c).