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Integral Calculus

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11 Mar 2010 15:03:35 IST

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integration of (1/log x)dx

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integration of (1/log x)dx

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Dasvidaniya

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11 Mar 2010 15:27:06 IST

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WHAT IS INTEGRATION 1/LOGx dx?

Asked in Lucknow at 3:11 PM on April 02, 2008

integrate using "integration by parts ".

write logx as logx . 1

and using ILATE rule ( inverse, log, algebraic, trigo, exponential in order of preference) we choose log x as first function and 1 as second function.

UVdx = UV dx - [ (dU/dx)(Vdx) ]

thus

logx.1 = logx1dx - [ d(logx)/dx . 1.dx ]
= x.logx - [ (1/x) .(x) ]
= x.logx - x + C

mukesh laiya

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11 Mar 2010 18:15:12 IST

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there is no difficult answere of it please ask your mother.

Deepak Aggarwal

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11 Mar 2010 21:57:49 IST

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where, li(x) : LogIntegral[x]: logarithmic integral

aqswdefr

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12 Mar 2010 23:14:17 IST

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put : u = 1/logx

I=-(ln10)* int. ( 1/u)du = -(ln10) ( ln|u|) + c

I= -(ln10) ( ln|1/logx||) + c

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