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Blazing goIITian

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17 Mar 2010 17:20:00 IST

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A pendulum is constructed as a light thin-walled sphere of radius R filled up with water and suspend

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A pendulum is constructed as a light thin-walled sphere of radius R filled up with water and suspended at the point O from a light rigid rod . The distance between the point O and the center of the sphere is equal to L. How many times will the small oscillations of such a pendulum change after the water freezes? The viscosity of water and the change of its volume on freezing are to be neglected.

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Vivek V Bhatnagar

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Joined: 15 Oct 2009

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18 Mar 2010 13:11:51 IST

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language of the question is unclear...

Why should the water freeze?

Aakash Anuj

Blazing goIITian

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18 Mar 2010 17:53:02 IST

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the water cannot freeze. plz refer to the qstn again

G.Reshma begum

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Joined: 28 Feb 2010

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18 Mar 2010 19:18:52 IST

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IF D WATER FREEZES WE CAN CONSIDER IT AS A RIGID BODY & CAL AS USALLY BUT BEFORE WE SHD CONSIDER VISCOUSITY & FORCE ON D WATER INSIDE BUT AS U SAID IF VISCOUSITY IS NEGLECTED DEN WE HAV 2 CONSIDER IT AS IDEAL LIQIUD WHICH HAV NO ROTATION BUT MOVES WID SYSTEM SO WE HAV 2 CAL D SAME WAY SO THERE WILL BE NO DIFFERENCE.

Venkatesh Ganesan

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18 Mar 2010 19:45:46 IST

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Firstly, the language of the question is unclear.

I have assumed that the water freezes by some external mechanism.

If the water freezes, and the volume occupied by the ice is the same as the original(as given in the question), then there will be absolutely no change in the small oscillations.Ice has lower density than water, so when both occupy the same volume, there would be some change in mass(change in mass is practically impossible but the question says so, so we assume it takes place).

Now all that has changed in the pendulum is the mass of the sphere, which affects the time period of oscillations in no way.

Hence, there is no change in the oscillations after the water is made to freeze.

. .

Blazing goIITian

Joined: 11 Apr 2009

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18 Mar 2010 20:17:57 IST

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no change.......the mass of the pendulum is changing ( as is evident frm the question)...and it wud have no effect on the oscillations............................but there is another aspect of it ....as the masss is changing den the weight is also changing so the length of string may change but u have said dat the string is light as well as rigid,.......so there is no change dat way also.....the question has so many constraints!

FORESTS

Blazing goIITian

Joined: 23 Jun 2009

Posts: 448

19 Mar 2010 12:22:32 IST

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it is an irodov problem

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