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Hot goIITian

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14 Mar 2010 13:00:52 IST

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a plane mirror in y-z plane is moving with -2^i m/s the object shown now starts moving with 3^i +^j

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a plane mirror in y-z plane is moving with -2^i m/s the object shown now starts moving with 3^i +^j -4^k m/s. what is the velocity of the image

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sanchit says ""Imagination has its own reality""

Blazing goIITian

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15 Mar 2010 18:55:04 IST

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ans is 5^i -j^ + 4k^

charanjit ghai

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15 Mar 2010 19:18:56 IST

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acc. to relative velocity,

Vm,o +Vo,g =Vm,g

Vm,o = -5i^-j^+4k^

this implies Vimage,g=-Vo,m=+5i^+j^-4k^

Dasvidaniya

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16 Mar 2010 16:02:30 IST

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plane mirror is in Y-Z plane

speed of mirror , Vm = - 2 ^i m /sec

speed of particle , Vo = 3 ^i + ^j + 4^k

from mirror and particle's vector form speed it it clear that both are moving in opposite direction in X axis......

and plane mirror is just moving in X axis ..SO speed image of particle's image will change only in X-axis and will remain same in Y-Z plane.

so the speed of image in X plane = 2Vm + Vo

= 2 ( -2^i ) + 3^i + ^j - 4^k

= (- ^i + ^j - 4^k) m/sec

Guruprasad Raghavan

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21 Mar 2011 12:33:16 IST

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i am getting answer as 5i-j+4k

can you please tell me what is wrong in my method

the velocity of image = (x+5-x)/1= 5 i

therefore velocity = 5i-j+4k

manisha jajoo

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21 Mar 2011 14:07:26 IST

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hi dasvidaniya can u pls say me y have u taken 2Vm

manisha jajoo

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21 Mar 2011 14:09:46 IST

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acc to me it shuld be 5i+j-4k????????

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