100ml of 0.1M HCL and 50ml 0.1M Ca(OH)2
...
H+ ions = n! x volume x molarity = 1 x 0.1 x 100 milli moles = 10 mmoles.
OH- ions = n! x volume x molarity = 2 x 50 x 0.1 = 10 mmoles.
Volume of the solution = 150 ml.
[H+] = [OH-] = 1/15 M
Concentration of both is same ..hence solution is neutral ... Ph = 7.
Aliter,
As HCl is monobasic and Ca(oh)2 is diacidic..
Taking equimolar concentrations of both, one volume of Ca(oh)2 neutralises 2 volumes of HCl.
hence, solution is neutral..Hence Ph = 7.
The end.
100ml of 0.1M HCL and 50ml 0.1M Ca(OH)2
...
H+ ions = n! x volume x molarity = 1 x 0.1 x 100 milli moles = 10 mmoles.
OH- ions = n! x volume x molarity = 2 x 50 x 0.1 = 10 mmoles.
Volume of the solution = 150 ml.
[H+] = [OH-] = 1/15 M
Concentration of both is same ..hence solution is neutral ... Ph = 7.
Aliter,
As HCl is monobasic and Ca(oh)2 is diacidic..
Taking equimolar concentrations of both, one volume of Ca(oh)2 neutralises 2 volumes of HCl.
hence, solution is neutral..Hence Ph = 7.
The end.