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Hot goIITian

Joined: 9 Mar 2010
Post: 142
9 Mar 2010 17:25:28 IST
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plz explain the concept of pseudo unimolecular reactions......thanks.
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plz explain the concept of pseudo unimolecular reactions......thanks.


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Forum Expert
Joined: 5 Mar 2010
Posts: 51
10 Mar 2010 11:03:16 IST
3 people liked this

A  and  B  react to produce  P:



If the initial concentration of the reactant  A  is much larger than the concentration of  B,   the concentration of  A  will not change appreciably during the course of the reaction The concentration of the reactant in excess will remain almost constant. Thus the rate's dependence on  B  can be isolated and the rate law can be written


Equation  

(1)

  represents the differential form of the rate law. Integration of this equation and evaluation of the integration constant  

C

  produces the corresponding integrated law.



Substituting  

[ B ]  =  c

  into equation  

(1)

  yields:



Integrating equation  

(2)

  gives:

The constant of integration  

C

  can be evaluated by using boundary conditions. At  

t  =  0

,   the concentration of  

B

  is  

co

.



Therefore


Accordingly is obtained:


If the decrease in concentration of  

B

  is followed by photometric measurement the  

Beer' Law

  must be taken into account.



Combining equation  

(4)

  and  

Beer' Law

A  =  absorbance,  e = molar absorbtivity with units of  L · mol -1 · cm -1
c  =  concentration of the compound in solution, expressed in  mol · L -1
Po =  radiant power for radiation entering;  P  =  radiant power for radiation leaving


gives the relationship between  

k'

  and  

lnA

:





According to equation  

(7)

,  a plot of lnA versus time should lead to a straight line whose slope is the pseudo-first order rate constant  

k'

.  The value of  

k'

  can then be divided by the known, constant concentration of the excess compound to obtain the true constant second order  

k

:




The  

pseudo-first order rate constant k'

  can be also determined from the  

half-life t 1 / 2

.





Hot goIITian

Joined: 9 Mar 2010
Posts: 142
17 Mar 2010 14:24:50 IST
0 people liked this

thanks so much sir....



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