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Integral Calculus
1/(cos3x - sin3x)Comments (24)
puneet1622
Cool goIITian
Joined: 29 Oct 2006
Posts: 43
10 Nov 2006 23:14:03 IST
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hiii
U have put the topic as definiite integral. Have u forgotten to put the limits of integration??? I am finding it difficult to solve it otherwise.
reply awaited .......
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12 Nov 2006 11:18:17 IST
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See when we are using the trick of putting 
/2 - x instead of x .... I think we should get some form where we eliminate the quantity in the log by adding to the original integral .. and this is not working here .. I think something wrong with the question itself .... !!!
/2 - x instead of x .... I think we should get some form where we eliminate the quantity in the log by adding to the original integral .. and this is not working here .. I think something wrong with the question itself .... !!! 
[ 
/2]log (tan x + cos x) is non-integrable.
[ 
/2]log (tan x + 14 Nov 2006 10:55:58 IST
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Hi ,arey yaar i think that u shud try foll .steps:
1)sepr8 deno.
2) put cosx as 1-t^2/1+t^2 & sinx as 2t/1+t^2 .
where t-> tan(x/2)
P.N : I TRIED this 1 on 3pgs B4 Being fed up. fromm next time do provide ans. & yEs LIMITS.
FROM WHERE DID U GeT THi$ Qn.
1)sepr8 deno.
2) put cosx as 1-t^2/1+t^2 & sinx as 2t/1+t^2 .
where t-> tan(x/2)
P.N : I TRIED this 1 on 3pgs B4 Being fed up. fromm next time do provide ans. & yEs LIMITS.
FROM WHERE DID U GeT THi$ Qn.
26 Nov 2006 23:34:52 IST
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Hi all,
I'm damn sure the problem is right. puneet1622 I haven't posted it wrong. A friend of mine (cleared JEE 2006) gave me this prob with a warning that everyone will tell me it is non-integrable but it is. Sadly, he didn't give me the answer can you help me get to the answer?
Cheers,
Lois
I'm damn sure the problem is right. puneet1622 I haven't posted it wrong. A friend of mine (cleared JEE 2006) gave me this prob with a warning that everyone will tell me it is non-integrable but it is. Sadly, he didn't give me the answer can you help me get to the answer?
Cheers,
Lois
27 Nov 2006 00:16:14 IST
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Hmmm....
this is interesting... finally we have something that challenges everyone! . The team who has tried to solve this one is one of the best in the country and everyone is on consensus on this one. Lois, why dont you try and get the answer for this one. If you can figure out the solution from your friend and the post it here then goIIT sends you a free goodie ! how about that?
cheers
~forum administrator
Hey man if you don't put the limits then the function's integral takes inverse hyperbolic functional slope . Anyways, this is the answer :-20 Jun 2007 18:32:55 IST
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Hey I have tried ...it may be correct just tell me otherwise I will have to revise the logarithmic properties.Well it is has to be integrated with reference to complex plane
because
ln z = ln |z| +i arg (z) where is z is a complex number.
(1/2) i ( ( x2+ polylog (2 , e 2ix ) ) where i =
-1
because
ln z = ln |z| +i arg (z) where is z is a complex number.(1/2) i ( ( x2+ polylog (2 , e 2ix ) ) where i =
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