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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Feb 2007 21:53:11 IST
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It was really good .Do you have some more shortcuts like this?
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4 Feb 2007 09:41:08 IST
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now Shakirshafi,Adarsh and Rama u deserve a salute!
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har kisi ko mukammal jahaan nahi milta,kahin zameen,toh kahin aasmaan nahi milta |
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6 Feb 2007 04:00:19 IST
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When 2 perpendicular lines are given in any question try solving it by taking them as axes, sometimes it becomes simpler to solve. When the options given for a seires is a function of n then try it by giving smallest possible value of n. If two or more options are correct for this n then try another higher value of n. In coordinate geometry please make a figure as a single figure has 1000 words associted with it. If the options are cyclic (e.g. it contains 3 variables a,b,c and options remain the same if we replace a by b, b by c, c by a) then take a=b=c and give it a try. (only if there is no relation between a,b,c in the question)
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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9 Feb 2007 00:19:25 IST
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Kab's ideas were cool .. good
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Puneet Agrawal
IIT Delhi
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9 Feb 2007 06:49:04 IST
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This is one of the easier method to find the equivalent Resistance. Consider a traingle ABC with resistors of resistance R on sides,AB,BC,AC.So there are 3 resistors. The forumula to find the Eq.R is (3-1)R/3. So consider a polygon of sides N with resistor of resistance R on each side. The gen.Formula is: EQ.R = (N-1)R/N.
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27 Feb 2007 22:18:23 IST
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WHILE USING STAR DELTA FOR SUBJECTIVE U WILL HAVE TO PROVE IT FIRST.SINCE IT IS NOT IN THE JEE PORTION .
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28 Feb 2007 14:40:37 IST
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hi , in maths some ques r like , in objective there r 4 option right so , do one thing put the options in the give ques equations both side prove it equal to zero , the options shows means comes equal to zero , is the ans of that ques dear ...... Post as much as u can so that every one can get benifit of that nice work .... go ooonnnnnnnnnnnn
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TOUCH THE SKY WITH GLORY WITH GUTTS |
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23 May 2007 01:12:10 IST
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hungryman ru hungry???? or overeaten???? dont do both cuz it'll not help u in jee...and ru asleep for 2 years????.....dude no subjective in jee..why wud anyone have to prove it thr then huh......get the jee pattern first dude....
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28 Aug 2007 12:21:31 IST
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EXPERTS PLS. CONTINUE THE NOBLE WORK!!!!!!!!!!!!!!!!!
IT WAS REALLY VERY HELPFUL!!!!!!!!!!!!!!!
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Stay Hungry. Stay Foolish. |
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28 Aug 2007 12:40:17 IST
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1.Area of triangle formed by ax2+2hxy+by2=0,lx+my+n=0 is n2(h2-ab)1/2 ----------------- am2-2hlm+bl2 2.If y=mx+c and eqn of circle is x2+y2=a2 then line will touch the circle if c2=a2(1+m2) and pt of contact is (-mc/1+m2,c/1+m2) 3.Line lx+my+n=0 will touch the circle x2+y2+2gx+2fy+c=0 if (lg+mf-n)2=(l2+m2)(g2+f2-c) 4.If r1-r2>d....One circle is completely inside the other... 5.If r1-r2=d...Two circles touch each other internally 6.If r1-r2<d<r1+r2.....Two circles intersect at two distinct points. 7.If r1+r2=d.....Two circles touch each other externally 8.If r1+r2<d.....Two circles lie far away from each other... Here,r1 and r2 r radius of the two circles...and d is the distance between their centres.. Hope these tricks helps u....will be postin more.....!!!
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28 Aug 2007 23:37:05 IST
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gudd
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Stay Hungry. Stay Foolish. |
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28 Aug 2007 23:52:55 IST
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Acid and Base-
There are three concepts of acids and bases-
1. Arrhenius Concept- According to this concept, an acid is a compound that releases H+ ions in water ; and a base is a compound that releases OH- ions in water. For example, HCl is an Arrhenius acid and NaOH is an Arrhenius base.
HCl H+ + Cl-
NaOH Na+ + OH-
2. Bronared- Lowry concept- According to this, an acid is any molecule or ion that can donate a proton (H+ ) and a base is any molecule or ion that can accept a proton. eg, HCl and NH3. HCl gas reacts with ammonia to form solid NH4Cl.
H
.. I
H-N-H + H-Cl [H-N-H]+ + Cl-
I I
H H
HCl is a proton donor and hence a Bronsted acid, while NH3 is a proton acceptor and a Bronsted base.
3. Lewis Concept- According to this, an acid is an electron-pair acceptor and a base is an electron-pair donor. eg, betwen H + and NH3, proton (H+ ) is a Lewis acid as it can accept an electron pair. Ammonia molecule has an electron pair which it can donate and is a Lewis base. The Lewis reaction between H+ and NH3 can be writen as-
H
.. I
H+ + H-N-H [H-N-H]+
Lewis I I Complex
acid H H
Lewis
base
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Stay Hungry. Stay Foolish. |
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31 Aug 2007 22:30:33 IST
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Hey good going. Plzzz tell some more links or shortcuts.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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31 Aug 2007 22:43:26 IST
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Hey chack this out- If you want to find the greatest term in the expansion of (x+y)n - Let A=(n+1)y/(x+y) Remember to put only the modulus or positive values of x,y in the formula for A If A is an integer, r = A, A+1 If A not an integer, r is an integer just before A. Eg- if A=25.3, r = 25. This value of r is for greatest term. Then use the general formula of finding term Tr+1 = nCr xn-ryr Hope this proves to be useful.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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