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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Jun 2007 22:54:37 IST
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Yaar, i think dere mst hve bn a prntng mstk.
A relatn b/n a,b,c hs 2 b dere.
In analogy 2 ur prob., i cn shw u smthng 2 mke u clr.
Lts c---------------tek ds as an example in acc. 2 ur problm.
, be the roots f eqn.ax2 + bx +c=0
ln[a(1+ b/a x +c/a x2)], let d whole expn. Insde bracket b 'E.'
lnE = lna + ln(1+ x ) +ln(1+ x )
= lna + ( + )x +1/2(2 + 2 )x2 +.....inf.
So, u cn c coeff. F xn vl b 1/n (-1)n(n + n )
Now +=b/a & =c/a
The n's dt u fnd here r in powrs excpt 1/n. All numrcls r in pwrs.
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priyam@crusade |
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12 Jun 2007 22:55:15 IST
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Yaar, i think dere mst hve bn a prntng mstk.
A relatn b/n a,b,c hs 2 b dere.
In analogy 2 ur prob., i cn shw u smthng 2 mke u clr.
Lts c---------------tek ds as an example in acc. 2 ur problm.
, be the roots f eqn.ax2 + bx +c=0
ln[a(1+ b/a x +c/a x2)], let d whole expn. Insde bracket b 'E.'
lnE = lna + ln(1+ x ) +ln(1+ x )
= lna + ( + )x +1/2(2 + 2 )x2 +.....inf.
So, u cn c coeff. F xn vl b 1/n (-1)n(n + n )
Now +=b/a & =c/a
The n's dt u fnd here r in powrs excpt 1/n. All numrcls r in pwrs.
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priyam@crusade |
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12 Jun 2007 22:55:42 IST
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Yaar, i think dere mst hve bn a prntng mstk.
A relatn b/n a,b,c hs 2 b dere.
In analogy 2 ur prob., i cn shw u smthng 2 mke u clr.
Lts c---------------tek ds as an example in acc. 2 ur problm.
, be the roots f eqn.ax2 + bx +c=0
ln[a(1+ b/a x +c/a x2)], let d whole expn. Insde bracket b 'E.'
lnE = lna + ln(1+ x ) +ln(1+ x )
= lna + ( + )x +1/2(2 + 2 )x2 +.....inf.
So, u cn c coeff. F xn vl b 1/n (-1)n(n + n )
Now +=b/a & =c/a
The n's dt u fnd here r in powrs excpt 1/n. All numrcls r in pwrs.
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priyam@crusade |
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12 Jun 2007 22:56:18 IST
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Agr kuc vi hlp hua to rate do na yr!!!!!!
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12 Jun 2007 22:57:57 IST
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Yaar, i think dere mst hve bn a prntng mstk.
A relatn b/n a,b,c hs 2 b dere.
In analogy 2 ur prob., i cn shw u smthng 2 mke u clr.
Lts c---------------tek ds as an example in acc. 2 ur problm.
, be the roots f eqn.ax2 + bx +c=0
ln[a(1+ b/a x +c/a x2)], let d whole expn. Insde bracket b 'E.'
lnE = lna + ln(1+ x ) +ln(1+ x )
= lna + ( + )x +1/2(2 + 2 )x2 +.....inf.
So, u cn c coeff. F xn vl b 1/n (-1)n(n + n )
Now +=b/a & =c/a
The n's dt u fnd here r in powrs excpt 1/n. All numrcls r in pwrs.
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