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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Please solve it immediately!!!!!
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rachit12 (363)

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u tried by wich method??

see da "letter to santa" in ma album ...!!!
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aggmegha90 (63)

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i messed up everything
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rachit12 (363)

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try by dis series.......
e= x/ 1 ! + x2/2 ! + x3/ 3 !............

see da "letter to santa" in ma album ...!!!
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rachit12 (363)

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srry its
e= 1+ x/ 1 ! + x2/2 ! + x3/ 3 !............

see da "letter to santa" in ma album ...!!!
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karansingh (401)

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check ur first question.

its wrong , i mean its terms are increasing, as sq(n) > n!

so infinite sum cant be fount out.
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aggmegha90 (63)

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but this given in the book, try the other two ques then!
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rachit12 (363)

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wich book u hav??

see da "letter to santa" in ma album ...!!!
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aggmegha90 (63)

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its career point package
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sahilgupta_iit (529)

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is the answer for the first question 7e?
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sboosy (3063)

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2.) T_k = \frac{k(k+1)}{k!} \\ \\ \sum_{k=0}^{k=n}\frac{k(k+1)}{k!} \ = \sum_{k=0}^{k=n} (\frac{k^2}{k!}+\frac{k}{k!}) = \sum_{k=0}^{k=n} (\frac{k}{(k-1)!}+\frac{1}{(k-1)!}) \\ \\ = (\frac{1}{0!}+\frac{2}{1!}+\frac{3}{2!}+...)+(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+....) \\ \\ \mbox{Splitting the first bracket into two we have} \\ \\ = (1+1+\frac{1}{2!}+\frac{1}{3!}+....)+(1+1+\frac{1}{2!}+\frac{1}{3!}+...)+(1+1+\frac{1}{2!}+\frac{1}{3!}+....) \\ \\ =3e
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allamraju (3422)

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1.sigma r^2(r+1)/r!
   splitting into partial fractions and writing sigma1/r!=e(r=0 to infinity),1/r-1!=e(r=1 to infinity) &so on,we get ans as 7e
 
2.sigmar(r+1)/r!
   following similar method,we get3e
 
   if ans are correct,please rate me

MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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aggmegha90 (63)

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can ne one answer third ques?
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aggmegha90 (63)

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any one for 3rd ques
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allamraju (3422)

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The third que is a bit tricky.try it by multying num & den of each term by 2,4.I tried but got a diff ans.If u get the ans please post solution

MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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