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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Roots of Polynomial
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RyuAmakusa (461)

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really sorry it is actually the same method as sir's i dint note it it was put in a diff. way though i cud hav noted it if i was a bit more careful.
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hsbhatt (3699)

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That doesnt take credit away from you, its an honest effort from you.
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RyuAmakusa (461)

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thank u sir
 
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little_genius (274)

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a5+b5+c5
 =a3.a2 + .....
= -3(a+1).a2+...........
=-3(a3+a2)+....
= -3( -3a-3 +a2)+.........
=9a+9-3a2 +...........
=9(a+b+c) + 27 -3(a^2+b^2 +c^2)
=9(0) +27 -3(3)
=27-9
=18
 
hence teh value is 18!!!!!

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little_genius (274)

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i hv done silly mistake somewhere.........but ma process is corect

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