well
how i reasoned out is...
consider pi*

2*

n^2+n/2
n^2+n/2 is the sum of nos till n
under the condn lim n-->infinity
bcoz of the

2
the term will be rational
so itll be a rational no *pi
n so ull have cos(pi *

2*

n^2+n/2) lim n--->inf
to be sumthin like cos(pi/2*r)...
so its gotta be zero
n i now think sin limit doesn exist??
edit were do u wan me 2 put ()??
i thought itwas clear
cn u point out the pt of cnfus.