IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

srujana

@neeraj

it isnt !!!

as we approach 0, ie in the interval [-1,1], the function is not differntiable as it makes infinite oscillations an it doesnt turn into a line..

this is the graph of the function till the greatest precision possible........still it isnt a staright line.....

hope u got it

neeraj_agarwal_1990

but we can go more close to the origin....it oscillates till the first point before origin.....and its not defined at origin...

but still there remains some doubt..

krish_in_stars

i think such type of a function doesn't exist since for continuity & non diffrenbiality both simutaneosly occur iff its graph has sharp turns a each of its x value which is impossible

rate the reply: [?]

johri_anshuman

neeraj, the function f(x)=x sin(1/x) is not differentiable at x=0

try out calculating the derivative at x=0... both LHD and RHD...

The function f(x) = x²sin1/x is differentiable at x=0.

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