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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Calculus urgent
Forum Index -> Integral Calculus like the article? email it to a friend.  
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thedumbheadwithnobrain (882)

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THE QUESTION IS ABSOLUTELY RIGHT

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allamraju (3410)

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I think that the right hand side must be 4xy(x2-y2).I nudged u the same but u said that the question is absolutely correct.But I still think it is so,b'coz then It can be solved as follows

(x-y)f(x+y)-(x+y)f(x-y)=[(x+y)2-(x-y)2](x+y)(x-y)

This gives f(x)=x3,just by comparing both sides and hence the two curves are

y2+x=0 and x2+y2=12 which are a parabola and a circle.

Thus,The area can be calculated by finding points of intersection and applying corresponding integrals.

MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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budokai_tenkaichi_returns (394)

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ne one with its solution??


SAIYANS ARE OF TRUE WARRIOR RACE . DONT UNDER-ESTIMATE US!
special theory of relativity ....i luv it...
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RyuAmakusa (461)

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allamraju very very true i totally accept u corrected the RHS i adjusted the LHS i have did this q before the sol is f(x)=x^3 that's
what i nudged him but he says the q is perfectly correct i dont know...
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thedumbheadwithnobrain (882)

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yup all u r right but who can say when there is a printing mistake.

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