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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Evaluate
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hsbhatt (4400)

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Olaaa!! Perrrfect answer. 828  [958 rates]

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To elaborate on the result that nadeem and bsg used,
 
We know from the fundamental theorem of algebra state and factor theorem that the polynomial
 
P(x) = anxn+an-1xn-1+...+ao has exactly n roots in the complex plane, say x1, x2, ..., xn
 
So, we can write P(x) = an (x-x1) (x-x2)...(x-xn)
 
Now, if this expression goes to zero for xn+1 which is not equal to any of the other roots, then the only possibility is that an = 0.
 
This means P(x) = 0 for all x.

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