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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 15:01:36 IST
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Hi meow Integrate it by parts Take 1 as first function and (tan inverse x )whole square as second function and then integrate it by parts
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1 Apr 2008 15:04:12 IST
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its a question which has come for the first time in the cbse 2008 paper.......it cannot be found in any of the iit/aieee/ncert prep textbooks/book of any kind...........
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1 Apr 2008 15:06:05 IST
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it came in the board's maths paper set 1 of outside delhi ....
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1 Apr 2008 15:07:04 IST
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@adidas ...if u r so sure of ur soln.....could u please the complete one...
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1 Apr 2008 15:18:15 IST
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hey adidas ,the problem that occurs when you integrate it is that you get the integrand as log sec theta limits frm 0 to pi/4 which cannot be easily integrated !!!
But if you are getting an ans with this method could you please post it ?
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1 Apr 2008 15:26:21 IST
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put tan^-1 x = t den d given [ ] [ ] becomes [0 ][  /4] 2t^2 sec^2 tdt 2[t^2tant]0-- /4 - [0 ][ /4] 2t tan t dt 2[ ^2/16] -2[t log sect]0- /4 - [ 0][ /4] log sect dt on simplification u will get d answer i.e tlogsect will repeat in integral o-pi/4 which will cancel hence u will get d answer
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1 Apr 2008 15:27:30 IST
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put tan^-1 x = t den d given [ ][ ] becomes [0 ][ /4] 2t^2 sec^2 tdt 2[t^2tant]0-- /4 - [0 ][ /4] 2t tan t dt 2[ ^2/16] -2[t log sect]0- /4 - [ 0][ /4] log sect dt on simplification u will get d answer i.e tlogsect will repeat in integral o-pi/4 which will cancel hence u will get d answer
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1 Apr 2008 15:40:08 IST
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Excuse me, but can you kindly tell me how you did integral 0 to pi/4 log secx dx? or how did you assume that it will cancel out? you see, im very stupid at this thats why i asked :)
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1 Apr 2008 15:42:05 IST
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aww ppl have started again
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Nitwit Blubber Odment Tweak
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1 Apr 2008 15:42:47 IST
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a useless thread that should be deleted at the earliest :D :D
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