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Community Discussion Question:
solve
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 16:53:03 IST
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edit !
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 16:57:50 IST
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I didn't.. But i've used complex numbers in solving some questions like integration of 1/(x^2+a^2) or same with power 4.. Friend of mine told me that's complex integration.. So i assumed that when you use complex numbers to solve integration problems it becomes complex integration :P :P.. What is it anyway?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 12:09:55 IST
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here is another solution..... cos^2x/1+tanx put tanx = t sec^2xdx = dt,,,,now substitute,,,,,, u will get cos^4x/1+t.....now we can write cos^4x = (cos^2x)^2 applying half angle formula of cos2x....we get cos^2x = 1+cos2x/2 now cos2x = 1-tan^2x/1+tan^2x....now substitute,,,,,,,this to question... further solution is here.... http://www.goiit.com/posts/list/integration-integration-60360.htm
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 12:10:24 IST
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plz rate me if u find me useful
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
     
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
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