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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Momentum...lets see who solves this...
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arpan1 (665)

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is the ans 3

if not, then what is the ans


pls post the diagram, if possible

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ananth_patri (595)

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sorry the answer is not 3 also.....well wat diag r u askin of??

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ananth_patri (595)

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well i have tried my best....plz solve it now....

The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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arpan1 (665)

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i am not getting a clear picture of this ques

i mean where are A and B standing. how are P and Q arranged..




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ananth_patri (595)

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see the diag... edited....

The only place where you will find success before hard work is in the dictionary
A winner never quits.....a quitter never wins......
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ananth_patri (595)

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some one plz solve......

The only place where you will find success before hard work is in the dictionary
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Conjurer (615)

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I will use the CoM method here.

Initially center of mass was at rest, and since there is no external force it is still at rest.

Let the velocity of platform P be x m/s wrt ground.

So velocity of A wrt ground = 5+x

0 = 50*(5+x) + 50x +10x+ 20*5/130

0 = 250 + 110x + 100

-350/110 = x

-35/11 =x

So P moves with a velcity 3.2 m/x app towards the left.

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sid.shah.90 (603)

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Is the answer 5 m/s towards right ?

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Siddhant Shah


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arpan1 (665)

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ananth, whatb is the ans given in the brilliant ans sheet

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priyesh (1605)

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Velocity of B w.r.t P = 0
 
=> velocity of B = velocity of P (w.r.t ground)
 
let velocity of P be v towards left w.r.t ground = velocity of B w.r.t ground
 
so velocity of A w.r.t ground = 5 - v
 
conserving momentum we get
 
50*(5 - v) + 20*5 - 50v - 10v = 0
 
=> v = 35/11
 
hence velocity of P = velocity of B w.r.t ground is 35/11 m/sec
 

"Imagination is more important than knowledge."
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arpan1 (665)

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priyesh


why is velocity of B = velocity of P (w.r.t ground)

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rohitkuruvila (311)

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is it 2.27 m/s (25/11)in the direction opposite that of A's motion
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ganesha1991 (1642)

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i too think the same as @ sid.shah.90


is it 5m/s
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arpan1 (665)

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this ques has been tried by a gud number of people

btw, it is a gud one and has been challenging our concepts

so it would be better if an expert solves it

all the best ...
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rohitkuruvila (311)

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