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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2008 13:48:13 IST
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yea thats wat i can nt get ...so will u provide some brief ideas
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17 Mar 2008 13:49:30 IST
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@akhil..if u r posting soln..pl do it only in the eve..i dun think many have tried it out yet
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Nitwit Blubber Odment Tweak
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17 Mar 2008 14:05:33 IST
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mgh=1/2mv2
v= 2gh
let the impact force be F
drawing FBD we can see that for the sphere,
two forces of eqal magnitude(F) act on it at angle 30 deg
so we have
2Fsin 30=(mv1+m 2gh)/ t
or
Ft=mv1+m2gh---------(i)
for one wedge
F sin 60=Mv2t due to change in momentum
F 3/2t=Mv2-----------------(ii)
from (i)a dn (ii) we have
2/3 Mv2=mv1+mv0
v0cos 60 e=v2cos 30+v1cos 60
putting values
ev0=v1+ 3 v2
substitute these values in above equations
v2=( 3)(1+e) m( 2gh)/2M+3m
v1=(2eM-3m)( 2gh)/2M+3m
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