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 Community Discussion Question:
Solve.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Mar 2008 09:46:28 IST
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5/2*mg
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mg(l/2) = 1/2 *I * ^2
Karthik , the rod is rotating about the hinge
so u gotta take I =ml^{2}/3 ??
By conserv of energy,
mgl/2=1/2*ml^{2}/3* ^2
gives = 3g/l
Now if F is d force by hinge on d rod
at vertical postition,
F-mg=m/*l/2*^2
F=5/2mg
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29 Mar 2008 10:04:33 IST
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Yes you are right elasti. Mistake by me there.
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Will nip in at times to solve problems :)
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