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Electricity

Blazing goIITian

Joined:	27 Jul 2007
Post:	3134

15 Jun 2008 14:23:01 IST

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1829

NODAL ANALYSIS

None

First read this article before seeing this thread-

http://www.goiit.com/posts/list/0/community-shelf-circuit-solving-was-never-so-easy-67415.htm#332300

I have posted there an example of rearranging circuits, here I am posting an example of solving circuits. U can also post ur doubts in circuits here only and I wud try my best to solve them.

The question is very common i.e., to find current in each branch.

In the second figure, I have applied 0 and V potential to A and B terminals respectively. As a,b,c are connected to A by a wire, A,a,b,c wud be at same potential.

Now the potentials of d,e,f are calculated as we are going from higher to lower potential of the battery, so we wud subtract battery's voltage from V.

Now comes the real application of Nodal analysis. U can consider either 0 or V-10/V-8/V-12 to be at higher potential according to ur own will. It will not alter the answer. Here I am considering 0 to be at lower potential and as current flows from higher to lower potential, the direction of current wud be as shown.

Now apply kirchoff's junction law at B. Means net current entering B = 0.

Now, I = V/R

so,

(V-12-0)/4 + (V-10-0)/4 + (V-8-0)/5 = 0

from here on solving, u wud get, V = 71/7.

Now u know potential difference across every resistor and u can now find current in each branch.

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reddevil_2009

Blazing goIITian

Joined: 29 Mar 2008

Posts: 1024

25 Jun 2008 23:57:55 IST

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plzzzzzz try to solve these tooooooo

ramyani chakrabarty

Blazing goIITian

Joined: 22 Apr 2007

Posts: 2537

26 Jun 2008 00:08:05 IST

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Tarin can do wonders.

u can see

http://www.goiit.com/posts/list/community-shelf-node-voltage-method-69857.htm

pink_ele

Blazing goIITian

Joined: 16 Jan 2007

Posts: 1836

26 Jun 2008 23:04:52 IST

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IF U SEE CLEARLY DEN-

here............potetial diff is marked on all points......ok..

points connected simply thru wire have same potential........

thus.....

we get......

I------------------------------------------C-----------------------------------I

I I----------------C----------------------I I

I-i-----------------C-----------------C--i------------C------------------------I

I--- --------------C---------------------i

here if we seperate capacitance frm v1 to v4

den rest of it is wheatstone bridge............ryt

so its capacitance equals=c

now one more c in parallel.........

net capacitance=2c

reddevil_2009

Blazing goIITian

Joined: 29 Mar 2008

Posts: 1024

27 Jun 2008 19:01:34 IST

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@pink_ele

PLZZZZZZ SPECIFY THE QUESTION WHICH U HAVE ANSWERED....

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