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Mechanics

Himanshu's Avatar
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25 Mar 2007 11:38:04 IST
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formulas!!!!!!!!!!!!
None

here are some shortcuts to find ...............  in motion in 1 dimension   1) to find the vel. in b/w the distance travelled   V1  = {v2  +  (v2 - u2/n)}1/2   2) a bullet is fired with certain vel. into a block of wood . it loses 1/nth of its initial speed after travelling a dist. x in the block . determine the total dist. penetrated by it before coming to rest.... ans)                     x'   =   {N2/ 2n - 1} x                 &nbs


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vir sharma's Avatar

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26 Mar 2007 13:42:02 IST
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gr8 goin man
Himanshu's Avatar

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26 Mar 2007 15:40:20 IST
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projectile thrown parallel to hor.

T = {2H/g}^1/2

R =u (2H/g)^1/2

K.E of projectile at the top
K(top) = Kcos^2$
Himanshu's Avatar

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27 Mar 2007 18:23:48 IST
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no other :(

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28 Mar 2007 11:21:48 IST
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nice going dude post some more
 
Himanshu's Avatar

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28 Mar 2007 12:01:59 IST
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thanx man.............
Himanshu's Avatar

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3 Apr 2007 12:38:03 IST
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okz

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3 Apr 2007 14:15:30 IST
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Suppose we slide a pearl thro a rod and the coeff of friction is #, then the max constant angular vel with which the rod can be rotated so that the bead doesnot slide is given as:
w=(#g/l) where l is the length of the rod....
Sanchay Gupta's Avatar

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4 Apr 2007 16:34:34 IST
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these r so simple n easy to remember
 
how did u get it plzz tell
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4 Apr 2007 21:27:54 IST
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Hey Himanshu, nice work. "Thathwamasi"
Himanshu's Avatar

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4 Apr 2007 21:32:33 IST
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thanku!!!!!!!!!!!!!!!!!!

Cool goIITian

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19 May 2007 11:31:27 IST
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hi

great work &a magnanimous personality .chimanshu u WILL WIN &ALL THE VERY BEST FOR A V BRIGGHT FUTURE

thnk u again for sharing this with us

georgek
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4 Jun 2007 16:30:18 IST
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u are welcome :)
Anubhav Srivastava's Avatar

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5 Jun 2007 12:59:11 IST
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good work
naga divya's Avatar

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5 Jun 2007 13:06:23 IST
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gr8 work
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18 Jul 2007 14:42:27 IST
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thanx :) :) :) :) :)

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18 Jul 2007 15:54:53 IST
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himashu u are an asset to goiit
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4 Aug 2007 00:58:13 IST
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thanx :) :)

may god bless u
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4 Aug 2007 07:33:48 IST
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acceleration of a system of bodies.

a = force/ mass ....forces not including tension n normal reaction

eg.
 2 masses attached on either sides of a massless pulley,
  force = m1g - m2g ,
mass =m1 +m2
a= m1g - m2g/m1 +m2

also applicable in rotation,
a = force/ mass

in case of a pulley wid moment of inertia = I &radius r
mass of pulley is taken as I/r2

a = (m1g - m2g)/m1 +m2 + I/r2


Dwarkanath Prabhu's Avatar

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5 Aug 2007 20:24:06 IST
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2 masses attached at the ends of a spring, of stiffness = k

transform d case into a one mass & spring system,
spring constant(k) remains same; the massof the new block taken as

1/ = 1/m1 + 1/m2
or

  =m1m2/m1 + m2

useful in solving shm, centre of mass & work, power energy probs.


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6 Aug 2007 19:40:40 IST
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projectile is at sum ht fr 2 timings sum of wich is time of flight
 
explanation.....well here the projectile is at same height fr 2 same times (a and b)
so time of light of o to a + time of flight frm o to b = total tym of flight...
 
(( o is the starting pt)
hope u got it now



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