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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2007 15:33:11 IST
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17 Jan 2007 19:32:43 IST
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1,3,5,7,9,11,13,
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18 Jan 2007 12:52:02 IST
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it iis arr 7 vacancies &9 people on round table such that no 2 vacancies r 2gether 8! * (8c7) * 6!
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20 Jan 2007 19:51:16 IST
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swordfish #2 result The solution given by ravitej is correct he deserves a prize
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21 Jan 2007 22:22:55 IST
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total no of people to be arranged arround a circular table = 16 no. of ways in which remaining 9 people may be arranged = ( 9 - 1)! = 8! the other 7 persons may be arranged among themselves in 7! ways. Thus total no. of ways = 8! * 7! = 203212800
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21 Jan 2007 23:06:52 IST
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16 7*7!/2!
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23 Apr 2007 16:34:03 IST
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hey i need ans. fr those ques. askd and also i want to be informed fr nxt contest....i wil prepare fr it
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14 May 2007 10:51:43 IST
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16*7
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simpler@INDIAN |
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14 May 2007 10:58:54 IST
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hi friends whr c'ld I find bitsat sample papers
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simpler@INDIAN |
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11 Jan 2008 22:22:19 IST
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since we have to select 7 ppls frm 16 but no consicutives shoul b selected then
lets start this way
consider a person as the head...
now including the head we have 8 members in which no two are consicutive..
there4 the total no. of ways 4 selection of 7 ppl frm 8 is
8c7
now the person just next to the head is excluded in the 1st case ,so now lets count him now and the other 7 ppl who were left before , so now again we have 8 members and no 2 of them are consicutive
again the total no of ways to select 7 ppl frm 8 is
8c7
now the case 1 is independable of the case 2 there4
total no of cases will be
8c7+8c7=2*8c7=2*8c1=16
ans is 16
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11 Jan 2008 22:58:49 IST
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This is easy. Total number of ways of selecting 7 people = 16c7 From this we have to subtract number of ways all three are consecutive =16 and also the number of ways inwhich two are consecutive = 16x 12c1 Therefore the final answer is = 16c7 - 16 - 16x12c1. Got it???
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11 Jan 2008 23:06:35 IST
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Somebody please rate me!!!
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17 Jan 2008 13:45:56 IST
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ffff
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27 Jan 2008 00:38:38 IST
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to select 7 people such that none is consecutive would be
First person can occupy any of the 16 chairs
Second person can sit in rest of the 13 chairs
Third in 11, Fourth in 9,Fifth in 7, Sixth in 5 ,proceeding in this way
Therefore total number of ways to sit= 16*13*11*9*7*5*3=2162160
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27 Jan 2008 00:43:50 IST
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