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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jun 2007 20:46:35 IST
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Tick Tock Tick Tock Tick Tock Tick Tock Tick Tock Tick Tock .............
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9 Jun 2007 20:53:35 IST
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is it tan(  -  ) [ 1- tantan)
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9 Jun 2007 22:11:41 IST
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The Time is out guys and I have got the winner , I can't believe that this guy has won:- And the winner is MR IITIAN007. Good job dude .Congrats. Wonderful answer user.It is alpha - beta whole devided by cos square alpha.Here, accept my rates , you deserve it.Please all the participants salute this guy.
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9 Jun 2007 22:21:36 IST
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hey yatin i request you to please post the detailed solution of ur ans.
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"Imagination is more important than knowledge."
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10 Jun 2007 15:59:16 IST
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Max value of tangent function is infinity ! But as you have asked maximum value of [(tan  ) - (tan  )] So, we will differenciate it w.r.t.  , we get, Solve this to get the desired answer!
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10 Jun 2007 18:05:17 IST
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hmm lets see this
let aplha equal pi/2 and beta equal to 0 so in numerator we have pi/2
and cos square alpha is 0.......so pi/2 by 0 is infinity..........
no i want to ask mr yatin how were we wrong initially.how can you express the max value of an function in terms of an variable ... it should be independent of the variables used i hope so........... correct
me if i am wrong
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you are in the competition to beat the competition
you work hard for a desired result |
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12 Jun 2007 15:27:48 IST
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Is it 2?
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21 Jun 2007 13:00:31 IST
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hey gag
ARe u sure this prob is corr
The prob shld be to find the min value
Max value is of course infinity
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devesh
La parada de tettas |
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21 Jun 2007 13:08:43 IST
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tan(alpha) - tan ( beta)=
tan ( A- B )(1+ tan(A) tan(B)
As tan x is an inc curve always
min val wud be wen A appraches B
Hence min(f)= lim A->B tan(A-B)(tanAtanB + 1)
mulyi div by A-B
using lim x->0 tanx/x=1
and tanA=tanB
min(f)= (A-B)(1+ tan(square) A)
wich is eq to
A-B * sec(square) A
=A-B /cos(sq)A
Sorry for joining a bit too late
I was ignorant of the prob
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devesh
La parada de tettas |
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21 Jun 2007 19:46:01 IST
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Gimme more pts yaar
Im dying for them
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devesh
La parada de tettas |
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21 Jun 2007 19:52:08 IST
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Hey then you must request all the goiitians . But I don't think anyone now will be interested to do that.But still.....try.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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22 Jun 2007 11:25:41 IST
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it is 0
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26 Jun 2007 13:00:37 IST
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yatin u typed a wrong ques...u asked max value which is of course infinity so lets rate all those who said infinity rather than those who told the min value which was not at all wat the question asked..
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30 Jun 2007 12:26:46 IST
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