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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: New Challenge (IIT'92)
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priyesh (1603)

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same confusion i have also got after 20 sec the box becomes massless
then how come ans is comin as 38.8 sec
coz remember no net force can be applied on a masssless body

"Imagination is more important than knowledge."
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karthik2007 (3399)

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Amazing sum man. Do post more. Hats off biki!

Will nip in at times to solve problems :)
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karthik2007 (3399)

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The thing to be remembered here is that the sledge has some mass. So the mass of the sand will be zero before 20 seconds, and after that, the sledge will move with its own mass.

Will nip in at times to solve problems :)
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rhd92781 (686)

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even if the sledge is considered massless (as assumed in the problem) :
the problem uses change in momentum to calculate force
after 20 s there is no change in momentum so no force applied as we know no force acts on a massless body
but it will have its velocity
so it should be covering the remaining distance with a constant velocity taking a total of 38 sec

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madman (239)

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wow that was something
the solutioin and the question were brilliant
and yes hats of to both waterdemon and biki

science-
the most fundamental
the most eternal
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kane (2199)

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congrats to both waterdemon and biki for solving it.i was just three steps away from the answer myself but being weak in calculus,couldn't find the solution till the end

there are numerous options besides I.I.T

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biki (1628)

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there should be no confusion............

consider the mass of the box = M

in the equ^n for change in momentum...

( M + 40 - 2t ) v - { M + 40 - 2( t + dt ) } v = Fdt
=> 2vdt = Fdt...gives the same result...

i m modifying my solution....

salman khan
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koooliitian (0)

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 i think the answer is appx 3.0985sec
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waterdemon (4732)

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Hey Dude,
The question has been already solved and we got the answer.

No prblems Anyways.............

Better luck next time
Cheers!!!!!!!!!!!!!!

Always available for help !

But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.







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laksy (4)

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hows tat -2t cming (M + 40 - 2t)v in this eq
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waterdemon (4732)

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Dude,
The sand is leaking out from the sledge at the rate of 2kg/s
as it has been given in th Question.

So the change in mass every sacond will be:
(M+40-2t)
Here M=mass of sledge as assumed by :"BIKI"
40 kg = weight of sand in the sledge.
So totla initial mass=M+40 kg.

And then he has given the conservation of momentum eq:
(M+40-2t)V - M+40-2(t+dt)V = F.dT

Here t+dt as assuming that the mass of sand that has
leaked out in small interval "dt" to be very small.

Hope you find it useful.
Rate if useful.

Cheers!!!!!!!!@@@!!!!!!!!!

Always available for help !

But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.







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laksy (4)

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if u dont mind can u just gimme the source..i mean..on net.any link to dis question..
i couldnt find in IIT 92 paper[:o]
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yash_pandit (10)

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well i got it less than 10 minutes
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laksy (4)

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Won't velocity also change over the time interval dt? Shouldn't that also be taken into consideration?
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