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11 Apr 2008 20:56:41 IST
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SHORT CUTS 4 AIEEEEEEEEEE/IIT JEE???????????
None
shortcuts 4 aieee/iit
all of u please post shortcuts &elimination methods 4
aieee/iit & some tips 4 saving time in aieee/iit
rates assured 4 gud replies!!!!!~!!!!
please!!!!!!!!
as it will b useful 4 all goiitians 2
crack aieee/iit.......
please post ur valuable
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please!!!!!!!@@!!!!!!
Comments (60)
prashant
Blazing goIITian
Joined: 20 Feb 2008
Posts: 456
11 Apr 2008 21:08:23 IST
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well dere r not much of them... but just one thing.
Always do ur paper with easy mind and yeah..!! dont avoid the truth that there is negative marking.. so no tukkas...
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12 Apr 2008 08:08:54 IST
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some tips............
#Some questions may have cunningly designed elaborate answer choices just to
mislead you, like the following.
Qn. The number of tangents to the curve x2 + y2 = 25 through the point (2,3) is
(1) two, given by -12(x2+y2-25) = (2x + 3y ? 25)2
(2) only one, given by 2x + 3y = 25
(3) 0
(4) four
Ans. The given curve is a circle with origin as centre and radius 5. The given point
(2,3) is at a distance 223+ = 13 < 5, the radius, from the centre; hence the
point is inside the circle and therefore no tangent is possible.
Ans choice: (3)
.
#. Verification Technique
Qn. The system of equations???has the solution (x,y,z) =
(1) (2,3,0) (2) (1,2,-3) (3) (0,-1,4) (4) (2,4,1)
Ans. Real solving will be lengthy and not necessary. Verify which set of values satisfies the given equations.
#Some questions may have cunningly designed elaborate answer choices just to
mislead you, like the following.
Qn. The number of tangents to the curve x2 + y2 = 25 through the point (2,3) is
(1) two, given by -12(x2+y2-25) = (2x + 3y ? 25)2
(2) only one, given by 2x + 3y = 25
(3) 0
(4) four
Ans. The given curve is a circle with origin as centre and radius 5. The given point
(2,3) is at a distance 223+ = 13 < 5, the radius, from the centre; hence the
point is inside the circle and therefore no tangent is possible.
Ans choice: (3)
.
#. Verification Technique
Qn. The system of equations???has the solution (x,y,z) =
(1) (2,3,0) (2) (1,2,-3) (3) (0,-1,4) (4) (2,4,1)
Ans. Real solving will be lengthy and not necessary. Verify which set of values satisfies the given equations.
12 Apr 2008 22:30:17 IST
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3 people liked this
Given by splashprabhu
acceleration of a system of bodies.
a =
force/ mass ....forces not including tension n normal reactioneg.
2 masses attached on either sides of a massless pulley,
force = m1g - m2g , mass =m1 +m2a= m1g - m2g/m1 +m2
also applicable in rotation,
a =
force/ massin case of a pulley wid moment of inertia = I &radius r
mass of pulley is taken as I/r2
a = (m1g - m2g)/m1 +m2 + I/r2
12 Apr 2008 22:30:53 IST
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2 people liked this
Given by chimanshu
1) to find the vel. in b/w the distance travelled
V1 = {v2 + (v2 - u2/n)}1/2
2) a bullet is fired with certain vel. into a block of wood . it loses 1/nth of its initial speed after travelling a dist. x in the block . determine the total dist. penetrated by it before coming to rest....
ans)
x' = {N2/ 2n - 1} x
where N is the amt of speed it loses (eg. if 1/10 th loses then N = 10)
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