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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 14:27:25 IST
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question 1 five cards are drawn successively with replacement from a well shuffled deck of 52 cards. what is the prob of 1.all five cards are spades 2. only 3 cards are spades question 2 a coin is biased so tht the head is 3 times as likley to occur as tail. if the coin is tossed twice find the probabilty distribution of number of tails !! i will rate u for sure eeven if u answer 1 !! see i m so good .. now pls help me ;-))
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URL=http://www.sparklee.com] [/URL] |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 14:30:06 IST
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13c5/52c5 is the probability of all 5 spades
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 14:32:36 IST
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13c3*39c2/52c5 is probability of exactly 3 spades 2tails : 1/16 1tail:6/16 0tails:9/16
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Q1) 1) (13/52)*(13/52)*(13/52)*(13/52)*(13/52) = 1/1024
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 14:33:48 IST
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yaar solve toh karo .. tell me the answer .. !! okay heres the answer q1, 1/1024
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URL=http://www.sparklee.com] [/URL] |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 14:34:22 IST
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thansk spidey;-)
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URL=http://www.sparklee.com] [/URL] |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 14:52:14 IST
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q2 is when x=0 then p(x)= 9/16 when x=1 then p(x)=6/16 when x=2 then p(x)=1/16
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URL=http://www.sparklee.com] [/URL] |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2008 16:54:49 IST
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prob for a head- 3/4 and tail-1/4
so for tail=0, we have (3/4)(3/4)=9/16 tail=1, 2C1(3/4)(1/4)=2*3/16=3/8 tail=2, (1/4)(1/4)-1/16
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