x and y are two integers such that 1<x<y and x+y<100. A person P knows the value of xy, while another person S knows that of x+y. They have the following conversation between them:

P: I can't find the numbers.

S: I knew you couldn't find them.

P: Thanks man, Now I can determine them.

S: So can I.

 

  WHAT ARE THE NUMBERS?

 

Well, the solution to this problem involves some lengthy calculations and computer assistance may be required. So, I am not asking for the solution. Just devise a way how to proceed.

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A coin is tossed repeatedly until either 5 heads or 5 tails have appeared. If n is the number of ways this can be done, then the divisors of n is:

a)6    b)12    c)18   d)20

 

hi friend its eazy if you know the value of xy and the value of x+y the you will get a quadratic in x and y but you have to neglect the value the comes out negative and you have to take the positive value

the ans to 2 is a,b,c as you can aciev this

suppose you have 10 box and 5 head and 5 tails then the number of ways by which they can be arranged is 10!/5!5!

hence the ans

bye