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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 18:33:03 IST
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HERE COMES A TRICKY FOURTH ONE...................... a and b are real numbers for which the equation x4 + ax3 + bx2 + ax + 1 = 0 has at least one real solution. Find the least possible value of a2 + b2. AWARD : 15 RATING POINTS REQUEST - THIS POST IS NOT FOR PEOPLE WHO HAVE SOLVED THIS Q. BEFORE OR HAVE AN IDEA FROM WHERE TO GET THE SOLUTION ( BY SOME UNKNOWN REFERENCES .............. )
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............tseb eht ma i |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 18:39:27 IST
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C'MON EVERYBODY.................
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............tseb eht ma i |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 18:41:28 IST
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well its definitely greater than 0 and smaller than 1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 18:43:46 IST
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UR CORRECT AATISH........
GO ON.................
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............tseb eht ma i |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 18:51:17 IST
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Is it 1!!!!!
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Best of luck to all my mates....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 18:51:58 IST
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NAHIN YAAR.........
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............tseb eht ma i |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:00:36 IST
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ANY REPLIES.............
ITS AS EASY AS IT GETS...........
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............tseb eht ma i |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:18:22 IST
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is nebody interested..........
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............tseb eht ma i |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:21:06 IST
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hey buddy i did it like this for x4 + ax3 + bx2 + ax + 1 = 0
let us put b=0 then we have =>x4 + ax3 + ax + 1 = 0 and now when x=1 for any single real solution of the eqn...
we have.. a=1
but if we take any other value of x (can be smaller or bigger or in negative)
a comes out to be greater than 1....
thats why for a2 + b2 to be least a=1 and b=0 so a2 + b2=1
Pls correct me where I am wrong..........
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Best of luck to all my mates....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:22:29 IST
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i guess we need to convert dis into a quadratic equation as der is atlast one real soltion............
wat do ya say......Aatish..........???/
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:23:44 IST
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Well have u tried to do so???
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............................................................................................................................................................................................
There's Light at the end of every Tunnel, so KEEP MOVING....
Best of luck to all my mates....
............................................................................................................................................................................................
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:24:40 IST
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hey......aatish......when x=1........we get......a= -1......
not +1 ......wat do ya say???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 19:26:41 IST
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