Algebra

Abhinav Jain's Avatar
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23 Jun 2009 11:47:53 IST
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8th class question
Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Algebra

Unit Fractions

 

Find natural numbers x,y,z such that

 

where

YOu may be surprised at just how many solutions exist.



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Abhinav Jain's Avatar

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23 Jun 2009 11:49:03 IST
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this is a question of my brothers 8th class holiday home work.plz tell the answer with a proper soln no matter how tough it is i'll explain it to him.
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23 Jun 2009 14:51:41 IST
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NugoRama's Avatar

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23 Jun 2009 14:59:02 IST
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1 month and 12 days ...No solution yet.
Abhinav Jain's Avatar

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23 Jun 2009 15:04:44 IST
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no re
Abhinav Jain's Avatar

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23 Jun 2009 15:05:08 IST
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m still stuck with this
Abhinav Jain's Avatar

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23 Jun 2009 17:22:48 IST
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Abhinav Jain's Avatar

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23 Jun 2009 20:15:10 IST
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........... plz sum 1 reply
®µD®A's Avatar

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23 Jun 2009 21:57:06 IST
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i am able to get 8 solutions lol :D trying to find a way ...

Cool goIITian

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24 Jun 2009 22:26:41 IST
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I guess there are infinite solutions

 

Abhinav Jain's Avatar

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25 Jun 2009 14:21:51 IST
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ya i also think there r infinite solns but it was mentioned that v would be surprised to no at just how many olns exist.

Blazing goIITian

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26 Jun 2009 09:25:54 IST
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There are infinite solutions to this question . will come up with a proof in some days


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26 Jun 2009 09:26:12 IST
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26 Jun 2009 13:51:12 IST
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x_1^2+y_1^2+z_1^2<x^2+y^2+z^2\  (x_i , y_i, z_i)<(x_{i+1} , y_{i+1}, z_{i+1})....................(1)          x>x1     y>y1          z>z1

Now observe

3xyzle x^2+y^2+z^2le xy+yz+zx

For proving this use the fact

x^2+y^2+z^2 >(x-y)^2+(y-z)^2+(z-x)^2       together with (x,y,z) ge 2 ...(Try it, I shall give it if u can't).

This proved suffices the case for x=y=z=1, by virtue of (1) above...

Thus no solutions exist!

 

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26 Jun 2009 13:54:44 IST
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So you are trying to say there exists no x,y,z satisfying the equation ?!?!?!?!

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26 Jun 2009 19:46:04 IST
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soumik see if we put x=y=z=1/15 then it is a soln of the given q but according to u no soln exists.hw would u explain this?

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27 Jun 2009 10:04:46 IST
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but dude you have taken x= y=z when given that

 

 

x<y<z?

Abhinav Jain's Avatar

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27 Jun 2009 19:03:52 IST
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ohk i forgt the condition
Soumik's Avatar

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28 Jun 2009 23:00:53 IST
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@ Abhinav, according to the qsn, x,y,z are naturals, since when did 1/15 become a natural no.....?

Rudra, go ahead with ur solution.....

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29 Jun 2009 09:18:35 IST
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the question asks for x,y,z to be natural but not 1/x,1/y,1/z ..



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