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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Jan 2008 18:39:06 IST
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A bag contains 50 tickets numbered 1,2,3,4,5,.........50 of which 5 are drawn at random and arranged in ascending order of the no. appearing on tickets (x1<x2<x3<x4<x5). Find probability that x3=30 .????????? plz solve wid explanations..................
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8 Jan 2008 20:28:51 IST
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since there are 50 tickets therefore total no. of ways of selecting 5
tickets are 50C3 .
since we want that 3rd ticket should be 30
and also we are arranging the tickets in ascending order
so if 3rd ticket is 30 therefore 1st and 2nd ticket should have the no.
less than 30 . i.e. from 1-29 .therefore no. of ways of selecting
first two tickets from 29 tickets = 29C2 .
and also last two tickets should have the no. greater 30
i.e. from 31-50,therefore no. of selecting last two tickets from 20 tickets
= 20C2.
therefore no. of favorable cases = 29C2 20C2
probability = 29C2 20C2 / 50C5
therefore ans. = 551/15134..
plss rate me if u find useful!!!
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I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME. |
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8 Jan 2008 20:35:58 IST
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akshay write the spelling of future correctly
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