A bag contains tickets numbered 1,2,3..........50 of which 5 tickets x1,x2,x3,x4,x5 are drawn at random and arranged in ascending order of magnitude x1<x2<x3<x4<x5.what is the probability that x3=30?
So, first two tickets have to be less than 30. There are 29 tickets less than 30 out of which two can be selected in 29C2 ways. Third ticket 30 can be selected in 1 way only. The remaining two are to be selected from 20 tickets numbered greater than 30 which can be selected in 20C2 ways.
Five tickets can be selected from 50 tickets in 50C5 ways.
So, req. probability = 29C2 X 1 X 20C2 / 50C2 = 551 / 15134 (Ans)
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