they are =(x+1)[(x-1)-i][(x-1)+i] =(x+1)[(x-1)^2-i^] =(x+1)[(x-1)^+1] =(x+1)[x^2-2x+2] =x^3-2x^2+2x+x^2-2x+2 =x^3-x^2+2 that is the answer if it is right plz.rate me
they are =(x+1)[(x-1)-i][(x-1)+i] =(x+1)[(x-1)^2-i^] =(x+1)[(x-1)^+1] =(x+1)[x^2-2x+2] =x^3-2x^2+2x+x^2-2x+2 =x^3-x^2+2 that is the answer if it is right plz.rate me
they are =(x+1)[(x-1)-i][(x-1)+i] =(x+1)[(x-1)^2-i^] =(x+1)[(x-1)^+1] =(x+1)[x^2-2x+2] =x^3-2x^2+2x+x^2-2x+2 =x^3-x^2+2 that is the answer if it is right plz.rate me
=(x-1)(x+2)(x-3)
=(x^2+x-2)(x-3)
=(x^3+x^2-2x-3x^2-3x+6)
=(x^3-2x^2-5x+6)
here is the answer
plz........... rate me.