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Algebra

Rohit's Avatar
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13 Apr 2009 23:15:08 IST
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A very good Question
None

In how many ways can 6 faces of a cube be painted with 6 different colours????

 

Please explain the answer also..

 

 


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STONE COLD RATTLESNAKE's Avatar

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13 Apr 2009 23:23:44 IST
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6!*6!+5!/2  Is it correct. Verify 

STONE COLD RATTLESNAKE's Avatar

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13 Apr 2009 23:24:37 IST
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this is very conceptual question, u can find the anser in rd sharma objective.
Rohit's Avatar

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13 Apr 2009 23:33:42 IST
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No,that's not the right answer.
Aditya's Avatar

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13 Apr 2009 23:45:08 IST
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it should be one........

Rohit's Avatar

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14 Apr 2009 00:16:34 IST
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I'm damn sure that 1 can't be the answer.For example,blue is opp. to green and then opp. to red,both cases are different...
Rohit's Avatar

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14 Apr 2009 12:02:16 IST
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More views please....
NugoRama's Avatar

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14 Apr 2009 12:07:10 IST
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posted the correct answer ...scroll down

Soumik's Avatar

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14 Apr 2009 12:24:12 IST
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Lay the cube flat with all its sides open on the floor facing u......now analyse it.

It's easier that way.

Siddhartha  Gupta's Avatar

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14 Apr 2009 12:29:22 IST
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shouldn't it be 6^6 ie 6×6×6×6×6×6
bharat  goswami's Avatar

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14 Apr 2009 12:37:48 IST
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i think ans. is 2880..

 


Blazing goIITian

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14 Apr 2009 12:43:57 IST
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since number of colors r specifiedand also no of sideso we have solution as 6P6=6factorial=720 ways
Rohit's Avatar

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14 Apr 2009 13:23:13 IST
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The answer is between 0 to 60 only..

14 Apr 2009 13:25:27 IST
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how can it b only 0-60...u hav 6 faces and 6 colors...!!!!!....it shud b 6^6...i.e. 6x6x6x6x6x6

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14 Apr 2009 13:27:03 IST
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I guess there is a simpler solution . Let us look at any combination so that we always face the side painted with the same color (say, red). In this case we have 5 sides left, therefore there is 5! = 120 ways to paint other 5 sides.
Now the uniqueness comes into play. Still holding the cube facing the selected (red) side, just rotating it around the axis, perpendicular to this selected side, we can put it in 4 different orientations, obviously repeating each other. THerefore we have to consider only one out of orientations, and the number of solutions is 5!/4 = 120/4=30

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14 Apr 2009 13:28:23 IST
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rohit's post gave me the idea.
Rohit's Avatar

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14 Apr 2009 13:32:38 IST
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The answer that i have is even smaller,but i don't trust it..So lets see what others say,but i liked nugorama bhaiyya's explanation.
14 Apr 2009 13:33:18 IST
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may b he is right...

New kid on the Block

Joined: 14 Apr 2009
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14 Apr 2009 14:23:05 IST
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the ans is 21

AViK's Avatar

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14 Apr 2009 21:04:16 IST
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Even i get it as 30....

 

say colours are P Q R S T U

 

let ny sides 1 & 2 (opp. sides) be painted with colours P & Q

 

so v are left with 4 sides n 4 colours so ways = 4!

 

but notice tht v can rotate it either way 2 get similar orientations...

 

like  RSTU ...STUR.... TURS ....RSTU (going in order) wud mean the same..

 

so ways fr the 4 sides = 4!/4 = 3! (v cud also hav considered circular PnC directly fr this!)

 

now if v keep ny one fixed (eg P on side 1) side 2 can hav "5" choices....according 2 which rest of the 4 colours wud b arranged...

 

So total ways = 5*3! = 30 ways...




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