IIT JEE , AIEEE Forum - Mathematics , Algebra

gabriel

PLEASE SOLVE THE FOLLOWING EQUATION:
3
4H + 18H - 2 =0

hit_ur_heart

here is the solution , but i dont think IIT will ask cubic equations
given equation is
4H^3+ 18 = 2
which can be written as H^3 + 9/2 = 1/2

take 2 variables x, y such that
3xy = 9/2
x^3 - y^3 = 1/2

now u can solve for x, y from here as we will get a equation which wil be easily converted into quadratic form.

after that the solution of the equation will be
H = x -y.
put it in the main equation to check the result.

regards.

edison

To solve cubic equations use following tips:

Let

,

be the roots of the cubic equation

a₀x³ + a₁x² + a₂x + a₃ = 0,

then

+

= - (a₁/a₀) .......(1)

+

= (a₂/a₀) .......(2)

= - (a₃/a₀) ......(3)

now solve equations (1), (2) and (3) to find the roots.

hit_ur_heart

mr . edison , try it again u will again generate the same equation , cubic equations are specially solved , remember it , they arent going to be solve by the way u have listed , again same equation will be generated

deepak_agarwal

hey this "hit ur heart"...kudos to u..really impressed by ur method

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