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[Post New]8 Nov 2006 14:38:20 IST
    Subject: algebra
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shruti (5)

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Please answer this:

if u,v belongs to real no., and 2*f(u)*cos(v) = f(u+v) + f(u-v)
then prove that for real x,
f( - x) + f(-x) = 0



Shruti
    
[Post New]10 Nov 2006 13:05:49 IST
    Subject: Re:algebra
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rahul.a (31)

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 f(u+v) + f(u-v)  = 2 . f(u) . cos(v)

put u = / 2 - x
      v =  / 2

so the equation becomes

    f( / 2 - x + / 2 )  + f( / 2 - x - / 2) = 2. f( / 2 - x).cos( / 2 )

f( - x) + f(-x) = 0  ( as cos( / 2 ) Answer
Rahul A
-- If you thing you can, you can. If you think you can't, you're right !! --
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[Post New]10 Nov 2006 16:55:45 IST
    Subject: Re:algebra
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puneet (3531)

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Great !!!!!!!
Perfect answer !!!!!!!!!!!!
Puneet Agrawal
IIT Delhi
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