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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: another on functions
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rockey (168)

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f(x)=(2x- )^3 +2x-cosx. the value of d/dx f inverse of x,x=
    
saurabh_reincarnated (230)

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is the ans. 1/2
if yes then i will give the sol...
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rockey (168)

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the ans is 1/3. & i got it too
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raulrag009 (1194)

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could u post the solution
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saurabh_reincarnated (230)

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look i am sending u a trick
 plz. rate me for it......
when u want to get some inverse, then just exchange the places of x and y. u can know it if u apply pure logic. remember: (f inv.) is reflection of f on line y=x
like here-
x=(2y-pie)3 +2y- cosy  ...............  A      y =f(x)
this is the inv. of given fn.
now see for x=pie we get y=pie/2 as one ans.
so differentiate A....
   and put y=pie/2   as x=pie
putting values we can get ans.
if any prob. nudge me!! or else...
 
PLZ. RATE ME IF U LIKE IT. i request it to all of u....
 
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saurabh_reincarnated (230)

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hey the ans is 1/2
and i am sure
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nadeemoidu (1184)

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This can be taken as a result d[ f-1(x)]/dx = reciprocal of d[f(x)] / dx

Here d[f(x)]/dx at x=pi/2 is 3.

So d[ f-1(x)]/dx = 1/3.

@saurabh : I think u'll get 1/3 with ur method also. just check ur working
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