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Algebra

Blazing goIITian

Joined:	13 Aug 2008
Post:	1313

25 Feb 2009 08:23:34 IST

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350

baye's theorem ...

None

Bag 1 contains 3 red and 4 black balls, Bag 2 contains 4 red and 5 black balls.

One ball is transferred from Bag 1 to Bag 2, then a ball is drawn from Bag 2.

The ball so drawn is found to be red in colour.

Find the probability that the transferred ball is black.

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Comments (2)

Kevin Arnold

Cool goIITian

Joined: 15 Jan 2009

Posts: 73

25 Feb 2009 08:58:28 IST

Like 2 people liked this

let R1 be the event that red is drawn frm the first bag....B1 b dat black ball is drawn from the 1st bag...R2 be the event dat red ball is drawn from the 2nd bag...

we need P(B1/R2)={ P(R2/B1) * P(B1)}/ { P(R1)*P(R2/R1) + P(B1)*P(R2/B1) }..............(By bayes' theoram of inverse probability)

now P(R2/B1)= 4/10.....P(R2/R1)=5/10.....P(R1)=3/7.....P(B1)=4/7.....

now substituting the above values we have our probability as = 16/31....

i dont see any amiss as long as theres a calculation error...

cheers!!!

Mirka

Blazing goIITian

Joined: 13 Aug 2008

Posts: 1313

25 Feb 2009 19:48:49 IST

Like 0 people liked this

thank you !

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