Home » Ask & Discuss » Mathematics. » Algebra « Back to Discussion



Algebra

apollo's Avatar
Blazing goIITian

Joined: 21 Mar 2009
Post: 345
3 Jun 2009 15:21:04 IST
0 People liked this
48
2338 View Post
best questions in maths.
None

1)In a tournament of n participants, each pair plays one game (no ties). Prove that exactly one of the following situations occurs:

(i) The league can be partitioned into two nonempty groups such that each player in one of these groups has won against each player of the other.
(ii) All participants can be ranked 1 through n so that i-th player wins the game against the (i + 1)st and the n-th player wins against the first.


Share this article on:

Comments (48)

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
3 Jun 2009 15:24:37 IST
1 people liked this

2)  An accurate 12-hour analog clock has an hour hand, a minute hand, and a second hand that are aligned at 12:00 o’clock and make one revolution in 12 hours, 1 hour, and 1 minute, respectively.  prove, that there is no time when the three hands are equally spaced around the clock, with each separating angle \frac{2 \cdot \pi}{3}.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
3 Jun 2009 15:25:01 IST
0 people liked this

3)Let A be an n \times n matrix whose elements are non-negative real numbers. Assume that A is a non-singular matrix and all elements of A^{-1} are non-negative real numbers. Prove that every row and every column of A has exactly one non-zero element.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
3 Jun 2009 15:26:07 IST
2 people liked this

4)Let f(x) = a \sin^2x + b \sin x + c, where a, b, and c are real numbers. Find all values of a, b and c such that the following three conditions are satisfied simultaneously:

(i) f(x) = 381 if \sin x = \frac{1}{2}.
(ii) The absolute maximum of f(x) is 444.
(iii) The absolute minimum of f(x) is 364.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
4 Jun 2009 20:43:24 IST
1 people liked this

5)In a sports meeting a total of m medals were awarded over n days. On the first day one medal and \frac{1}{7} of the remaining medals were awarded. On the second day two medals and \frac{1}{7} of the remaining medals were awarded, and so on. On the last day, the remaining n medals were awarded. How many medals did the meeting last, and what was the total number of medals ?

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
4 Jun 2009 20:44:13 IST
1 people liked this

6)Determine all positive roots of the equation x^x = \frac{1}{\sqrt{2}}.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
4 Jun 2009 20:45:04 IST
1 people liked this

7)If x,y,z are real numbers satisfying relations
x+y+z = 1 \quad \textrm{and} \quad \arctan x + \arctan y + \arctan z = \frac{\pi}{4},
prove that x^{2n+1} + y^{2n+1} + z^{2n+1} = 1 holds for all positive integers n.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
4 Jun 2009 20:45:57 IST
1 people liked this

8)Prove that for an arbitrary pair of vectors f and g in the space the inequality
af^2 + bfg +cg^2 \geq 0
holds if and only if the following conditions are fulfilled:
a \geq 0, \quad c \geq 0, \quad 4ac \geq b^2.


Hot goIITian

Joined: 30 Apr 2009
Posts: 111
4 Jun 2009 20:56:41 IST
2 people liked this

Look, 381=a/4 +b/2 +c.Therefore,a+2b+4c=1524.Now, Sin is maximum at 90 degree i.e the maximum value is sin(90)=1.So,a+b+c=444.............eq 1And,Sin is minimum at -90 degree i.e. the minimum is Sin(-90)= -Sin(90)= -1.Hence, a+(-b)+c=364............eq2.or,a+c=b+364...............eq3.Now adding both equations,2(a+b)=804So, a+b=402....eq4Substituting equation 4 in equation 3,b=38.Solving further,c=323,a=77
Soumik's Avatar

Blazing goIITian

Joined: 31 Jul 2008
Posts: 1266
5 Jun 2009 13:52:58 IST
2 people liked this

Rahul, I cud only read the 1st qn....the others are having technical errors....

1st one is a sitter...

See there can be only 2 conditions :-

1) All have lost to some other player, at least once

                             OR

2) 1 of the guys have not suffered defeat.....

If 1st condition holds true then we can always frame such a sequence.....However if 2nd is true then...

Let (a_i,a_j) denote the winner between ai & aj.....

Let a_{k

So 1 of my groups A\equiv \boxed{a_k,a_{k

N\equiv \boxed{a_x}\\ \ 1\le x\le n\\ \ x\ne k\\ \ x\ne k

These 2 groups satisfy the 2nd condition....

Soumik's Avatar

Blazing goIITian

Joined: 31 Jul 2008
Posts: 1266
5 Jun 2009 14:00:56 IST
2 people liked this

I don't think roots (Except x=\frac{1}{2}) can be exactly determined for x^x=rac{1}{sqrt{2}}

However interval has to be (0,1).....Obvious from graph itself (Though drawing the graph was not easy either)

Seems that's the only real root of the eqn.

Rahul  Duggal's Avatar

Scorching goIITian

Joined: 10 May 2008
Posts: 289
6 Jun 2009 13:53:36 IST
4 people liked this

6. not too sure

another way of checking the domain is xx is trivially greater than 1 for x>1 whereas

 so   an observation here tells us that x is an integral power  of 

checking for  we find they are solutions.

now we can note

but xx is strictly increasing for x= 1/2n          where n  z+ and n>2

®µD®A's Avatar

Blazing goIITian

Joined: 12 Apr 2008
Posts: 2717
6 Jun 2009 14:12:43 IST
2 people liked this

5) is the answer 36 and 6 ?
Rahul  Duggal's Avatar

Scorching goIITian

Joined: 10 May 2008
Posts: 289
6 Jun 2009 14:33:19 IST
2 people liked this

8

the LHS of the inequality can be intepreted as a quadratic eqn in f       (a0)

as the inequality is 0, we want the curve above x axis or atmost 1 intersection with x axis so a>0

to justify the slackness in the inequality we have . assuming f,g are not null vectors for if they are the inequality is trivially true

4ac > b2 . now as b2>0 and a>0 it is justified to say c>0

i've proved a>0. the equality can be confirmed if f,g are null vectors

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
7 Jun 2009 00:13:33 IST
1 people liked this

rahul and soumik , that was good work.

 

RUDRA,  can u kindly show your working please ?  ( u r right RUDRA).   but i want the working

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
7 Jun 2009 00:24:06 IST
1 people liked this

5)

 

The trigonometric relation is equivalent to

 


\frac{x+y+z-xyz}{1-xy-xz-yz}=1
or xyz-xy-xz-yz-x-y-z+1=0. But since x+y+z=1,
0=xyz-xy-xz-yx+x+y+z-1=(x-1)(y-1)(z-1).
Hence one of x, y, z is 1.

 

WLOG suppose x=1. Now y=-z

and

 

 

hence x^{2n+1}+y^{2n+1}+z^{2n+1}=1+y^{2n+1}-y^{2n+1}=1

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
7 Jun 2009 00:27:24 IST
1 people liked this

6)

 

Taking \ln both sides, we have that

\additional \displaystyle x\ln x=\frac{1}{2}\cdot\ln \frac{1}{2}} \\\Rightarrow \frac{x}{\frac{1}{2}}=\frac{\ln\frac{1}{2}}{\...

but since a\geq b \Rightarrow \ln a\geq \ln b, we must have one of \displaystyle \max \left\{\frac{x}{\frac{1}{2}},\frac{\ln\frac{1}{2}}{\ln x}\right\}\geq 1 \geq \min \left\{\frac{x}{\frac{1}..., so we must have x=\frac{1}{2}

 

am  i rite? or is there any fallacy in my method ?

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
7 Jun 2009 00:31:18 IST
1 people liked this

OK  CONTINUING WITH THE QUESTIONS ,

9)The professor tells Roger the product of two positive integers and Kevin their sum. At first, nobody of them knows the number of the other.

One of them says: You can't possibly guess my number.
Then the other says: You are wrong, the number is 136.

Which number did the professor tell them respectively? Give reasons for your claim.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
7 Jun 2009 00:33:03 IST
1 people liked this

10)

 

Two people, A and B, play the following game: A start choosing a positive integrer number and then, each player in it's turn, say a number due to the following rule:

If the last number said was odd, the player add 7 to this number;
If the last number said was even, the player divide it by 2.

The winner is the player that repeats the first number said. Find all numbers that A can choose in order to win. Justify your answer.

apollo's Avatar

Blazing goIITian

Joined: 21 Mar 2009
Posts: 345
7 Jun 2009 00:34:13 IST
1 people liked this

11)

 

Consider the set S of 100 numbers: 1; \frac{1}{2}; \frac{1}{3}; ... ; \frac{1}{100}.
Any two numbers, a and b, are eliminated in S, and the number a+b+ab is added. Now, there are 99 numbers on S.
After doing this operation 99 times, there's only 1 number on S. What values can this number take?




Quick Reply


Reply

Some HTML allowed.
Keep your comments above the belt or risk having them deleted.
Signup for a avatar to have your pictures show up by your comment
If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Find Posts by Topics

Physics.

Topics

Mathematics.

Chemistry.

Biology

Parents

Board

Fun Zone

Sponsored Ads