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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 11:37:42 IST
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what is boolean algebra
pls reply
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 15:06:31 IST
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http://en.wikipedia.org/wiki/Boolean_Algebra
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 16:48:49 IST
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heres the qn
if a,b and c are the elements of a boolean algebra, then a.b+c(a' +b')=
(a)a.b (b)c
(c)a.b+c (d)none
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 21:26:21 IST
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its something done in computers..and also maths... awesome thing to do... rtype it in wikipedia...rate please..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 21:28:07 IST
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I think the answer should be d).Am i correct??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Apr 2008 17:31:56 IST
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Solve using truth table: Let F = a.b + c.(a' + b') = a.b + c.(a.b)'
A B C F 0 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 1 0 0 0 1 0 1 1 1 1 0 1 1 1 1 1
clearly. (a.b) + c is the correct answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 19:05:27 IST
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it is c
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 19:50:22 IST
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well from Ronaldooo post refer to the truth table we infer that where ever c is 1 F is 1 and only other place where F is 1 but c in not 1 is for 1 1 0 so the fn is be c+a.b well this is just from logic there are proper methods. u can do it if u learn more of boolean algebra
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