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Algebra
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3 Dec 2009 07:32:24 IST
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analytical expression for nth term can be found by generating polynomial which I learned from Hari sir.
We have to find : such that
Adding these three :
except 1st terms all terms are 0 since they follow an+2 = 3an+1 + 2an
we know a1 = 1 and a2 = 1. Expand RHS and compare coefficients of xn to find out the analytical expression for an ( feeling a bit lazy so didn't do till last step :D )
however I can't figure out what will be the sum of the series













5 = 3 x 1 + 2 x 1
17 = 3 x 5 + 2 x 1
61 = 3 x 17 + 2 x 5
217 = 3 x 61 + 2 x 17
so general term is given by : tn = 3tn-1 + 2tn-2