IIT JEE , AIEEE Forum - Mathematics , Algebra

hrishabhsharma

hey guys or gals i m giving u a challange. Can u prove that 1+1=0????

sboosy

$[tex]\\ \ (2)^2 = (-2)^2 \\ \mbox{Now cancelling the powers ...(well to prove 1+1 = 0...we can do any such thing!!!)we get}\\2=-2\\ \rightheadedarrow \ 2+2 = 0 \\ \mbox{dividing by 2} \we\ get\\ 1+1 = 0 !!![\tex]$

$[tex]\\ \mbox{well i just wanted to try latex}[\tex]$

elastiboysai

good latexing boosy

hmm

looks like evry1 has learnt latex except me
i tooll have 2 learn soon

konichiwa2x

great going buddy!

Radon222

wow, sboosy your latex rocks man !!!!!!!!

hrishabhsharma

hey sboosy ur answer is wrong bcoz in first u took the value "2= -2" but this is incorrect value.. now everybody plz keep attention on this equation-----

-6=-6

=4-10=9-15

=4-10+25/4=9-15+25/4

=(2)^2-(2*2*5/2)+(5/2)^2=(3)^2-(2*3*5/2)+(5/2)^2

=[2-(5/2)]^2=[3-(5/2)]^2

=2-(5/2)=3-(5/2)

=2=3

=3-2=0

=1=0----------(1)

By equ. (1)

=1+1=0+0

So

=1+1=0

plz reply, Is this right or wrong, and plz give ur reason also...

and plz rate it.....

arpitsr

Nopes!! urn't correct.....u can't take sqr rut like that.......

[2-5/2]^2 = [3-5/2}^2 u got to solv like ths......

a^2 - b^2 = 0

by prop,(a+b)(a-b) = 0

(2-5/2+3-5/2)(2-5/2 -3 +5/2) = 0

since 2nd term isn't 0 so 1st has to b and it is.......

vineetnegi

prove
1+1=10

sandeepramesh

binary numbers Razz

srujana

@elasti

frm whr do u get those smileys????

Ask & Discuss Questions with Community & Experts