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tarinbansal (3937)

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In the figure a square is given with each side=1 unit.
Four points A,B,C,D are taken arbritrarily on the 4 sides of the square and a quadrilateral is formed by joining them with sede lengths a,b,c,d.
 
Find the minimum value of a2 + b2 + c2 + d2 .
Will be posting solution tomorrow.
Till then give the best solutions to win salutes.
 
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tarinbansal (3937)

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Rate me if you think the question was useful and challenging.

The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.

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rajatsen91 (1389)

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( a^2 + b^2 + c^2 + d^2)/4>=(abcd)^1/2
this min is reached when a=b=c=d
when this happens, then a=b=c=d = 1/(2)^1/2
so min value of a^2 + b^2 + c^2 + d^2 is 4*1/2 = 2

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tarinbansal (3937)

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Rajat,
your answer is right but the solution not satisfactory.
How can you prove that min is reached when a=b=c=d?

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